Maths about me: a first-lesson icebreaker for A Level Maths
A first lesson of Year 12 or Year 13 that gets everyone doing maths straight away: number facts built from a birthday, ‘Who am I?’ riddles from GCSE and Year 12, the four 4s challenge and two short proofs. Everything is on paper and nothing personal is collected.
- Level
- A Level Maths (Year 12 and Year 13)
- Time
- 40 minutes, plus a 10-minute extension
- Topics
- Proof; Sequences and series; Algebra and functions; Exponentials and logarithms
- Equipment
- The starter is non-calculator. A calculator is useful for task A.
Suggested timings
| Part | Time | What |
|---|---|---|
| Starter | 5 min | Quick questions on the board |
| Main: task A | 12 min | Maths about me |
| Main: task B | 10 min | ‘Who am I?’ in pairs |
| Main: task C | 13 min | Four 4s |
| Extension | 10 min | Fast finishers or homework |
Starter (5 minutes)
‘Who am I?’ riddles on the board as students arrive.
- I am a positive integer and my square is 6 more than me. Who am I?
- I am 1 + 2 + 3 + … + 20. Who am I?
- I am log2 32 − log3 9. Who am I?
- I am the coefficient of x2 in (1 + x)6. Who am I?
Main activity (35 minutes)
Task A: Maths about me (12 min)
Work through Sam’s made-up numbers first. Then write the same facts about your own numbers on paper.
- Sam was born on day 18 of month 12 in 2008. Write 12 and 2008 as products of prime factors, and find their HCF and LCM.
- Write 2008 in binary.
- How many terms of the arithmetic sequence 12, 18, 24, … are less than 2008, and what is their sum?
Task B: ‘Who am I?’ in pairs (10 min)
Solve these with a partner. Then each write a riddle of your own, on a topic from last year, with exactly one answer and swap.
- I am the only positive integer n with 2n = n2 + 7. Who am I?
- Find every two-digit number that equals the sum of its digits plus the product of its digits.
- I am the sum to infinity of a geometric series with first term 6 whose first two terms add to 10. Who am I?
Task C: Four 4s (13 min)
Use exactly four 4s to make each target. Allowed: +, −, ×, ÷, brackets, powers, √ and ! (4! = 24). You may join two 4s to make 44. Other answers are possible.
- Make 0 and 24.
- Make 19.
- Make 1024.
- Make 11 using √.
Extension (10 minutes)
For fast finishers.
- Prove that the difference between a two-digit number and the number with its digits reversed is always a multiple of 9.
- Prove that n3 − n is a multiple of 6 for every integer n.
For teachers
Teacher notes and full worked answers
- Nothing personal is collected: students work on paper, and nothing is typed into the site or stored. If a student would rather not use a real birthday, any date works.
- Pairs for task B: each student writes one riddle with exactly one answer and swaps with a partner, who checks that only one number fits.
- Mindset prompts for the first lesson (for you to read out or put on the board; nothing is collected or stored): ‘A time maths felt hard, and what helped’; ‘One topic from last year I could teach a friend’; ‘What I do when I am stuck’; ‘How I want this class to feel’.
- The extension proofs are direct proofs of the kind in the Proof topic: ask for a concluding sentence each time.
Starter
- 3
- x2 − x − 6 = (x − 3)(x + 2) = 0
- x = 3
- 210
- 20 × 21 / 2 = 210
- 3
- 5 − 2 = 3
- 15
- 6C2 = 15
Task A: Maths about me
- 12 = 22 × 3, 2008 = 23 × 251; HCF = 4, LCM = 6024
- 2008 = 8 × 251, and 251 is prime (not divisible by 2, 3, 5, 7, 11 or 13, and 172 > 251)
- HCF = 22 = 4; LCM = 23 × 3 × 251 = 6024
- 11111011000
- 2008 = 1024 + 512 + 256 + 128 + 64 + 16 + 8
- 333 terms; sum 335 664
- 12 + 6(n − 1) < 2008 gives n − 1 < 332.67, so n = 333 (the last term is 2004).
- S = 333/2 × (12 + 2004) = 335 664
Task B: ‘Who am I?’ in pairs
- 5
- Try n = 1, 2, 3, 4, 5: 2n − n2 = 1, 0, −1, 0, 7.
- For n ≥ 5 the gap keeps growing, so 5 is the only answer.
- 19, 29, 39, 49, 59, 69, 79, 89 and 99
- 10a + b = a + b + ab gives 9a = ab, so b = 9.
- 18
- 6 + 6r = 10 gives r = 2/3
- S∞ = 6 / (1 − 2/3) = 18
Task C: Four 4s
- 44 − 44 = 0 and 4 × 4 + 4 + 4 = 24
- 44 − 44 = 0
- 16 + 8 = 24
- 4! − 4 − 4/4 = 19
- 24 − 4 − 1 = 19
- 44 + 4/4 = 1024
- 45 = 1024
- 44/(√4 × √4) = 11
- √4 × √4 = 4, and 44 ÷ 4 = 11
Extension
- (10a + b) − (10b + a) = 9(a − b)
- The number is 10a + b; its reverse is 10b + a.
- The difference is 9a − 9b = 9(a − b), a multiple of 9.
- n3 − n = (n − 1)n(n + 1)
- It is the product of three consecutive integers.
- One of any two consecutive integers is even, and one of any three is a multiple of 3, so the product is a multiple of 2 × 3 = 6.
The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.
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