The equation $e^{2x} - 5x = 0$ has a root $\alpha$. Show that this equation can be rearranged into the iterative formula $x_{n+1} = \frac{1}{2}\ln(5x_n)$.
Mark scheme and worked answer
- M1 for isolating the exponential term to get $e^{2x} = 5x$.
- M1 for taking the natural logarithm of both sides: $2x = \ln(5x)$.
- A1 for dividing by 2 to write it in the required iterative form $x_{n+1} = \frac{1}{2}\ln(5x_n)$.