Part of the age structure for one local authority. Ages are given as age last birthday.
| Age | 20–24 | 25–29 | 30–44 | 45–59 |
|---|---|---|---|---|
| People | 9800 | 10 450 | 29 700 | 27 000 |
- Explain why a histogram should be drawn with frequency density rather than frequency. [1]
- Calculate the frequency density for each class. [2]
- Estimate the number of people aged 40 to 49 (last birthday), stating an assumption you make. [2]
Worked solution and mark scheme
- The classes have different widths (5, 5, 15 and 15 years), so the area of each bar, not its height, must show the number of people. B1
- '20–24' means $20 \le$ age $\lt 25$: width 5. Frequency densities (people per year of age): M1
$9800 \div 5 = 1960$, $10\,450 \div 5 = 2090$, $29\,700 \div 15 = 1980$, $27\,000 \div 15 = 1800$. A1 - Ages 40 to 49 run from 40 to 50: 5 years of the 30–44 class and 5 years of the 45–59 class.
$\tfrac{5}{15} \times 29\,700 + \tfrac{5}{15} \times 27\,000 = 9900 + 9000 = 18\,900$ people. M1 A1
Assumption: people are spread evenly across the ages within each class.