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Edexcel IAL P2 January 2024 mark scheme and question paper (WMA12/01)

Pure Mathematics 2 (P2), sat in January 2024. The buttons open Pearson's own files.

The official paper and mark scheme

Sit it under exam conditions: open the paper, press Start timer, press Finish when time is up, then mark it against the mark scheme.

Marked it? Worked solutions to 3 similar P2 questions are just below, then every P2 topic to practise.

3 P2 questions like these, with worked solutions

Written and checked by us, not taken from the Pearson paper. Try each one, then tap "Worked solution" to see every step and its marks.

  1. Further Trigonometry · 5 marks

    Solve the equation 2cos2⁡x−sin⁡x−1=0 for 0∘≤x≤360∘.

    Worked solution
    1. M1 for using the identity cos2⁡x=1−sin2⁡x to rewrite the equation: 2(1−sin2⁡x)−sin⁡x−1=0.
    2. M1 for simplifying to a quadratic in sin⁡x: 2sin2⁡x+sin⁡x−1=0.
    3. M1 for factorising the quadratic to (2sin⁡x−1)(sin⁡x+1)=0.
    4. A1 for finding the solutions from sin⁡x=0.5, which are x=30∘,150∘.
    5. A1 for finding the solution from sin⁡x=−1, which is x=270∘.
  2. Algebraic Methods · 5 marks

    When f(x)=2x3+px2+qx+1 is divided by (2x−1) the remainder is 2. When f(x) is divided by (x+1) the remainder is -4. Find the values of p and q.

    Worked solution
    1. M1 for applying the Remainder Theorem with x=0.5: f(0.5)=2⟹2(18)+p4+q2+1=2.
    2. M1 for simplifying the first equation: 14+p4+2q4=1⟹p+2q=3.
    3. M1 for applying the Remainder Theorem with x=−1: f(−1)=−4⟹−2+p−q+1=−4⟹p−q=−3.
    4. M1 for solving the simultaneous equations (e.g., subtracting them gives 3q=6).
    5. A1 for stating q=2 and p=−1.
  3. Proof · 5 marks

    (a) Prove by exhaustion that the square of any integer leaves a remainder of 0, 1 or 4 when it is divided by 5. [4]

    (b) Hence show that the last digit of a square number is never 2, 3, 7 or 8. [1]

    Worked solution

    (a) Considers every case: n=5k, 5k±1, 5k±2 (or 5k, 5k+1, 5k+2, 5k+3, 5k+4), k an integer M1

    Squares at least two cases correctly, e.g. (5k±1)2=25k2±10k+1 M1

    All cases correct: (5k)2=5(5k2); (5k±1)2=5(5k2±2k)+1; (5k±2)2=5(5k2±4k)+4 A1

    Conclusion: every integer is in one of the cases, so the remainder is always 0, 1 or 4 A1 (cso)

    (b) A whole number ending in 2 or 7 leaves remainder 2, and one ending in 3 or 8 leaves remainder 3, on division by 5; by (a) a square leaves remainder 0, 1 or 4, so it cannot end in 2, 3, 7 or 8 B1

More on these topics: Further Trigonometry · Algebraic Methods · Proof

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What's on this paper

What this paper is like

WMA12/01: question by question

Labels and topics are ours, read from the WMA12/01 paper (checked 2026-11-01); marks as printed. Tap a number to practise that topic.

  1. Q1Remainder theorem with a constant (3 marks) · P2 Algebraic Methods
  2. Q2Coefficient in a binomial expansion (3 marks) · P2 The Binomial Expansion
  3. Q3Circle through a point and a tangent (6 marks) · P2 Circles
  4. Q4Exponential graph with an asymptote (9 marks) · P2 Logarithms and Exponentials
  5. Q5Sigma notation and a recurrence (8 marks) · P2 Sequences and Series
  6. Q6Log equation reduced to a cubic (8 marks) · P2 Logarithms and Exponentials
  7. Q7Wheat yield as a geometric series (9 marks) · P2 Sequences and Series
  8. Q8Counter-example and an algebraic proof (6 marks) · P2 Proof
  9. Q9Trig equations in degrees (14 marks) · P2 Further Trigonometry
  10. Q10Tangent to a curve and an enclosed area (9 marks) · P2 Differentiation (stationary points), P2 Integration (definite integrals and area)

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Where is the P2 January 2024 mark scheme?

The mark scheme button above opens Pearson's own copy.

What are the grade boundaries for IAL P2 January 2024?

On Pearson's grade boundaries page (opens in a new tab), under January 2024.