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Examiner Insights · IAL P2 (WMA12)

What the examiners said about IAL P2 (WMA12) — and exactly what to do about it

We read every Pearson Edexcel examiner report for WMA12 from June 2024 to June 2025, mapped each question to a topic, and turned the comments into a checklist of the mistakes that cost the most marks.

  • 4exam series analysed
  • 4examiner reports read
  • 41questions mapped to topics
  • 8top mark-losing mistakes

Summaries are in our own words with links to the originals. Predictions are informed guesses, not a guarantee.

Ranked for January 2027

What to focus on for January 2027

IAL units are sat in January, June and October. The October 2026 series is next; the ranking below is for your next sitting, whichever it is. Ranked by how often each area appeared, how many marks it carried and how weakly it was answered.

Informed prediction, not a guarantee: any topic on the specification can be examined.

  1. 1

    Factor and remainder theorems, and proof

    Two questions in every series (about 13–14 marks), including a proof each time.

    High confidenceJune 2024 Q4, Q5Oct 2024 Q3, Q11June 2025 Q4, Q10
  2. 2

    Arithmetic and geometric series in context

    Two questions in most series (9–15 marks); context and r are where marks go.

    High confidenceJune 2024 Q2, Q10Jan 2025 Q1, Q4June 2025 Q7
  3. 3

    Logarithms with every stage shown

    Every series; the instruction to show all stages is repeatedly ignored.

    High confidenceOct 2024 Q6, Q8June 2025 Q6
  4. 4

    Areas and the trapezium rule

    In every series (5–11 marks).

    High confidenceOct 2024 Q1June 2025 Q3, Q5
  5. 5

    Trig identities and equations (radians)

    One question each series, 7–12 marks.

    Medium confidenceJune 2024 Q8Oct 2024 Q9June 2025 Q8
  6. 6

    Circles

    Every series; signs of the centre and midpoints.

    Medium confidenceJune 2024 Q7Oct 2024 Q10June 2025 Q2
  7. 7

    Optimisation

    Two optimisation questions in January 2025, one in June 2025 (11 marks).

    Medium confidenceJan 2025 Q3, Q9June 2025 Q9
Mistakes library

The 8 mistakes that cost the most marks

Ordered by how often and how widely they were reported. The first 5 are free in full; Pro unlocks the fix and a worked example for every other one.

#1Logarithms: log laws not shown, and roots not rejected

What examiners saw: The paper instructs candidates to show all stages; combining logs without showing the law, removing logs incorrectly, and keeping a root that makes a log undefined all lose marks.

Fix: One log law per line, then remove the log (log₂ A = 3 ⇒ A = 2³). Reject any root that makes an argument ≤ 0 and say why.

Worked example (our own): Solve log₂(x + 2) + log₂ x = 3.

Loses marks

  1. x(x + 2) = 3 …
  2. x = 2 or x = −4

Earns the marks

  1. log₂(x(x + 2)) = 3 (addition law)
  2. x² + 2x = 2³ = 8 ⇒ x² + 2x − 8 = 0 ⇒ (x + 4)(x − 2) = 0
  3. x = 2 (x = −4 is rejected: log₂ x needs x > 0)

Why: Show the log law you use on its own line, remove the log correctly (2³, not 3), and reject any root that makes a log undefined, saying why.

Reported in: WMA12/01 October 2024 Q6; WMA12/01 June 2025 Q6; WMA12/01 June 2024 Q3

#2Trapezium rule: strip width and brackets

What examiners saw: The strip width is found from the number of ordinates instead of strips, and the outer bracket is missing. Some use the calculator instead of the log laws needed to reach an exact form.

Fix: h = (b − a)/n for n strips; write ½h[first + last + 2(middle ones)] in full.

Worked example (our own): Use the trapezium rule with 4 strips to estimate ∫₀² √(1 + x²) dx.

Loses marks

  1. h = 2/5
  2. ½ × h × y₀ + y₄ + 2(y₁ + y₂ + y₃)

Earns the marks

  1. 4 strips ⇒ h = (2 − 0)/4 = 0.5, x = 0, 0.5, 1, 1.5, 2
  2. y = 1, 1.1180, 1.4142, 1.8028, 2.2361
  3. ≈ ½ × 0.5 × [1 + 2.2361 + 2(1.1180 + 1.4142 + 1.8028)] = 2.98 (3 s.f.)

Why: h is (b − a) ÷ number of STRIPS (not ordinates), and the big bracket must contain everything: ½h[ends + 2 × middles].

Reported in: WMA12/01 October 2024 Q1; WMA12/01 June 2025 Q5; WMA12/01 January 2025 Q7

#3Factor theorem: "= 0" not set up from the start; roots not justified

What examiners saw: f(−3) is evaluated but not set equal to 0 at the outset (the "= 0" appears late or only by implication), and questions asking how many real roots there are get an answer without a reason.

Fix: Write "f(−3) = 0" first. To justify the number of roots, factorise fully and use the discriminant of the quadratic factor.

Worked example (our own): (x + 3) is a factor of f(x) = x³ + ax² − 4x − 12. Find a.

Loses marks

  1. f(3) = 27 + 9a − 12 − 12 …

Earns the marks

  1. (x + 3) is a factor ⇒ f(−3) = 0
  2. −27 + 9a + 12 − 12 = 0 ⇒ 9a = 27 ⇒ a = 3

Why: The factor theorem is f(−3) = 0 for the factor (x + 3). Write "= 0" at the start, not at the end.

Reported in: WMA12/01 January 2025 Q5; WMA12/01 June 2025 Q4; WMA12/01 June 2024 Q4

#4Proof: examples instead of general cases; weak conclusions

What examiners saw: Proof by exhaustion answered by trying numbers; disproof by counter-example without a conclusion; confusion between rational and irrational numbers.

Fix: Cover every case with algebra (3k, 3k + 1, 3k + 2), and finish with a sentence stating what has been shown.

Worked example (our own): Prove that the square of any integer leaves a remainder of 0 or 1 when divided by 3.

Loses marks

  1. 1² = 1, 2² = 4 → remainder 1, 3² = 9 → remainder 0, 4² = 16 → 1 … so true.

Earns the marks

  1. Every integer is 3k, 3k + 1 or 3k + 2 for some integer k.
  2. (3k)² = 3(3k²) → remainder 0
  3. (3k + 1)² = 3(3k² + 2k) + 1 → remainder 1
  4. (3k + 2)² = 3(3k² + 4k + 1) + 1 → remainder 1
  5. All cases covered, so the square of any integer leaves remainder 0 or 1.

Why: Checking examples is not proof by exhaustion; the cases must cover every integer.

Reported in: WMA12/01 June 2024 Q5; WMA12/01 October 2024 Q11; WMA12/01 January 2025 Q8; WMA12/01 June 2025 Q10

#5Geometric series: r the wrong way up; sum to infinity with |r| ≥ 1

What examiners saw: Dividing the wrong way gives r = 1.25 for a series that converges; simultaneous equations in a and r are set up but not solved.

Fix: r = later term ÷ earlier term. Only use S∞ = a/(1 − r) when |r| < 1.

Worked example (our own): A geometric series has second term 20 and third term 16. Find its sum to infinity.

Loses marks

  1. r = 20/16 = 1.25 … no sum to infinity

Earns the marks

  1. r = u₃/u₂ = 16/20 = 0.8
  2. a = 20/0.8 = 25
  3. S∞ = a/(1 − r) = 25/0.2 = 125 (valid since |r| < 1)

Why: r = later term ÷ earlier term. A sum to infinity exists only when |r| < 1, so an r of 1.25 should make you check.

Reported in: WMA12/01 June 2025 Q7; WMA12/01 January 2025 Q4

Paper by paper

Every paper we analysed, question by question

Topics are ours (matched from each report's question-by-question comments). We don't reproduce the questions: open the official paper from our past-paper page.

June 2025 · WMA12/01 · 10 questions · 75 marks

Official examiner report

QTopicMarks
Q1Binomial expansion (positive integer n)6
Q2Coordinate geometry: circles7
Q3Further integration & the trapezium rule5
Q4Algebraic division & the factor theorem9
Q5Further integration & the trapezium rule6
Q6Laws of logarithms & solving equations10
Q7Geometric sequences & series; Sum to infinity9
Q8Trig identities & equations8
Q9Further differentiation11
Q10Mathematical proof4
January 2025 · WMA12/01 · 10 questions

Official examiner report

QTopicMarks
Q1Arithmetic sequences & series
Q2Binomial expansion (positive integer n)
Q3Further differentiation
Q4Sum to infinity; Geometric sequences & series
Q5Algebraic division & the factor theorem
Q6Coordinate geometry: circles
Q7Further integration & the trapezium rule; Laws of logarithms & solving equations
Q8Mathematical proof
Q9Further differentiation
Q10Trig identities & equations
October 2024 · WMA12/01 · 11 questions · 75 marks

Official examiner report

QTopicMarks
Q1Further integration & the trapezium rule5
Q2Sequences by recurrence; increasing, decreasing & periodic sequences7
Q3The remainder theorem; Algebraic division & the factor theorem7
Q4Further differentiation7
Q5Binomial expansion (positive integer n)7
Q6Laws of logarithms & solving equations5
Q7Arithmetic sequences & series6
Q8Exponentials & logarithms8
Q9Trig identities & equations7
Q10Coordinate geometry: circles10
Q11Mathematical proof6
June 2024 · WMA12/01 · 10 questions · 75 marks

Official examiner report · This paper on our past-paper page

QTopicMarks
Q1Binomial expansion (positive integer n)5
Q2Arithmetic sequences & series7
Q3Laws of logarithms & solving equations6
Q4Algebraic division & the factor theorem; The remainder theorem8
Q5Mathematical proof6
Q6Exponentials & logarithms; Further integration & the trapezium rule9
Q7Coordinate geometry: circles6
Q8Trig identities & equations12
Q9Further differentiation; Further integration & the trapezium rule8
Q10Geometric sequences & series8
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Your mistakes vs the examiners' hot-spots

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Top 10 mistakes examiners see in IAL P2 (WMA12)

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Sources

Where this comes from

We read the examiner report for every series from June 2024 to June 2025 in full and matched each question to a topic; marks come from the published mark schemes where the per-question totals could be checked against the paper total.

FAQ

What do examiners say students get wrong in IAL P2 (WMA12)?

The most repeated points are: Logarithms; Trapezium rule; Factor theorem. Each one on this page has the fix and, where free, a worked example showing the wrong and right method.

Which IAL P2 (WMA12) topics come up most?

In the material we analysed, the biggest areas were Factor and remainder theorems, proof, Sequences and series, Exponentials and logarithms.

Is this a prediction of the January 2027 paper?

No one outside the exam board knows what will be on the next paper. The "focus" list is an informed prediction from how often topics appeared and how weakly they were answered; it is not a guarantee, so revise the whole specification.

Where does this information come from?

We read 4 Pearson Edexcel examiner reports (June 2024, October 2024, January 2025, June 2025) in full, summarised them in our own words and linked each point to the original.