A Level Math Revision Free diagnostic
Themed maths

Spot the mistake relay and maths taboo for A Level Maths

An end-of-term lesson that is fun and still useful: teams race to find the slip in worked solutions built on the most common exam mistakes, then play maths taboo and pictionary with the course’s vocabulary.

Level
A Level Maths (Year 12 and Year 13)
Time
39 minutes, plus a 10-minute extension
Topics
Algebra and functions, the binomial expansion; Integration by parts and R cos(θ − α); The binomial and normal distributions; Proof
Equipment
A calculator is needed for task B.

Download student sheet (PDF)Answers (PDF)

Suggested timings

PartTimeWhat
Starter5 minQuick questions on the board
Main: task A12 minRelay, part 1
Main: task B12 minRelay, part 2
Main: task C10 minMaths taboo
Extension10 minFast finishers or homework

Starter (5 minutes)

Spot the slip: each line has one mistake.

  1. Using cos θ ≈ 1 − θ2/2, cos 2θ ≈ 1 − 2θ2/2 = 1 − θ2
  2. The x2 term of (1 + 3x)4 is 6 × 3x2 = 18x2
  3. X ~ B(4, 0.5): P(X > 3) = 1 − P(X ≤ 4) = 0

Main activity (34 minutes)

Task A: Relay, part 1 (12 min)

Each worked solution has exactly one mistake. Find it, then give the correct answer.

  1. Find ∫ xex dx. Working: xex + ex + c.
  2. (6, 5) lies on y = f(x). Find the matching point on y = f(2x). Working: a stretch with scale factor 2 parallel to the x-axis gives (12, 5).
  3. Write 3 cos θ + 4 sin θ as R cos(θ − α). Working: R = 5, tan α = 3/4, α = 36.9°.

Task B: Relay, part 2 (12 min)

Each worked solution has exactly one mistake. Find it, then give the correct answer.

  1. f(x) = 2x and g(x) = x + 3. Find fg(1). Working: g(f(1)) = g(2) = 5.
  2. X ~ N(20, 22). Find P(X < 22). Working: with a continuity correction, P(X < 22.5) = P(Z < 1.25) = 0.894.
  3. f(x) = x3 − 2x − 5. Show that f(x) = 0 has a root between 2 and 3. Working: f(2) = −1 and f(3) = 16.

Task C: Maths taboo (10 min)

Describe the word to your team without saying it or any of the banned words.

  1. Describe INTEGRAL without saying: area, under, curve, anti.
  2. Describe VECTOR without saying: direction, magnitude, arrow, size.
  3. Describe POLYNOMIAL without saying: power, term, degree, quadratic.
  4. Describe FUNCTION without saying: input, output, machine, map.

Extension (10 minutes)

For fast finishers.

  1. Prove that x2 − 6x + 10 > 0 for all real x. Working: squares are always positive, so it is positive.

For teachers

Teacher notes and full worked answers

Starter

  1. 1 − 2θ2
    • Bracket the whole angle: 1 − (2θ)2/2 = 1 − 4θ2/2
  2. 54x2
    • (3x)2 = 9x2, so 6 × 9x2
  3. 1/16
    • P(X > 3) = 1 − P(X ≤ 3) = P(X = 4) = 1/16

Task A: Relay, part 1

  1. xex − ex + c
    • Mistake: a sign. By parts, ∫ u dv = uv − ∫ v du.
    • xex − ∫ ex dx = xex − ex + c
  2. (3, 5)
    • Mistake: f(2x) is a stretch with scale factor ½ parallel to the x-axis.
    • (6 ÷ 2, 5) = (3, 5)
  3. 5 cos(θ − 53.1°)
    • Mistake: the ratio is upside down. R cos α = 3 and R sin α = 4, so tan α = 4/3.
    • α = 53.1°

Task B: Relay, part 2

  1. 8
    • Mistake: fg means do g first, then f.
    • fg(1) = f(g(1)) = f(4) = 8
  2. 0.841
    • Mistake: a continuity correction is only for approximating a discrete distribution.
    • P(Z < 1) = 0.841
  3. Add the conclusion
    • Mistake: no conclusion. f(2) < 0 < f(3) and f is continuous on [2, 3], so there is a change of sign and a root between 2 and 3.

Task C: Maths taboo

  1. Sample clue: ‘Undoes differentiation, like adding up lots of thin strips.’
    • The word is integral. Any clue that avoids the banned words is fine.
  2. Sample clue: ‘Something with both how big and which way, like a velocity.’
    • The word is vector. Any clue that avoids the banned words is fine.
  3. Sample clue: ‘An expression like 3a³ + 2a − 7, with whole-number indices.’
    • The word is polynomial. Any clue that avoids the banned words is fine.
  4. Sample clue: ‘A rule that turns each number you put in into exactly one number.’
    • The word is function. Any clue that avoids the banned words is fine.

Extension

  1. (x − 3)2 + 1 ≥ 1 > 0
    • Mistake: the reasoning is incomplete, and a square can be 0.
    • x2 − 6x + 10 = (x − 3)2 + 1. Since (x − 3)2 ≥ 0, the expression is at least 1, so it is always positive.

The same answers are in the answers PDF. Every answer was recomputed by computer before publishing.

Practise the topics

Maths art maths · Summer escape room maths · Summer puzzle pack maths · All themed maths

More for lessons: Weekly starters · Skill Builders · Worksheet builder · Competition maths