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Edexcel IAL P4 January 2023 mark scheme and question paper (WMA14/01)

Pure Mathematics 4 (P4), sat in January 2023. The buttons open Pearson's own files.

The official paper and mark scheme

Sit it under exam conditions: open the paper, press Start timer, press Finish when time is up, then mark it against the mark scheme.

Marked it? Worked solutions to 3 similar P4 questions are just below, then every P4 topic to practise.

3 P4 questions like these, with worked solutions

Written and checked by us, not taken from the Pearson paper. Try each one, then tap "Worked solution" to see every step and its marks.

  1. Vectors · 5 marks

    Two lines have vector equations l1:r=(2i+3j)+t(i−j+k) and l2:r=(−3j−2k)+s(i+j+k). Prove that the lines intersect and find the position vector of their point of intersection.

    Worked solution
    1. M1 for setting up equations for the components: 2+t=s, 3−t=−3+s, and t=−2+s.
    2. M1 for solving the first two equations simultaneously. From s=2+t, substituting into the second gives 3−t=−3+(2+t).
    3. M1 for solving to find 2t=4⟹t=2, which means s=4.
    4. M1 for checking consistency in the third (z) equation: t=2, and −2+s=−2+4=2. Since 2=2, the lines intersect.
    5. A1 for substituting t=2 or s=4 back to find the point of intersection: 4i+j+2k.
  2. Parametric Equations · 7 marks

    A curve has parametric equations x=t+1, y=t3−12t.
    (a) Find the values of t at the stationary points on the curve. (3)
    (b) Find the coordinates of the stationary points. (2)
    (c) Determine the nature of each stationary point. (2)

    Worked solution

    (a) dydx=3t2−121=3t2−12   M1 A1. Set =0: t2=4⇒t=±2   A1.
    (b) t=2: (3,−16); t=−2: (−1,16)   A1 A1.
    (c) d2ydx2=6t⋅dtdx=6t (since dtdx=1)   M1. t=2: 12>0 ⇒ minimum; t=−2: −12<0 ⇒ maximum   A1.

  3. Differential Equations · 4 marks

    Use the method of separation of variables to find the general solution to the differential equation: dydx=xy Express your answer in the form y2=f(x).

    Worked solution

    Separate the variables by multiplying both sides by y and dx: M1
    ydy=xdx.
    Integrate both sides: ∫ydy=∫xdx. M1
    y22=x22+C. A1
    Multiply entirely by 2 to isolate y2:
    y2=x2+2C. (Note: 2C can just be written as a new constant K). A1

More on these topics: Vectors · Parametric Equations · Differential Equations

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What's on this paper

What this paper is like

WMA14/01: question by question

Labels and topics are ours, read from the WMA14/01 paper (checked 2026-11-01); marks as printed. Tap a number to practise that topic.

  1. Q1Partial fractions, then a binomial expansion (9 marks) · P4 Partial Fractions, P4 The Binomial Expansion
  2. Q2Parametric equations to a Cartesian equation (6 marks) · P4 Parametric Equations
  3. Q3Area of a region by integration (5 marks) · P4 Integration
  4. Q4Substitution with an exponential (9 marks) · P4 Integration
  5. Q5Implicit curve: vertical tangents (7 marks) · P4 Differentiation
  6. Q6Position vectors and a line (8 marks) · P4 Vectors
  7. Q7Rates of change for a balloon (12 marks) · P4 Differentiation, P4 Differential Equations
  8. Q8Parametric curve: tangent and area (11 marks) · P4 Parametric Equations, P4 Integration
  9. Q9Proof by contradiction about multiples of 3 (8 marks) · P4 Proof

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Questions students ask

Where is the P4 January 2023 mark scheme?

The mark scheme button above opens Pearson's own copy.

What are the grade boundaries for IAL P4 January 2023?

On Pearson's grade boundaries page (opens in a new tab), under January 2023.