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Edexcel IAL P1 June 2023 mark scheme and question paper (WMA11/01)

Pure Mathematics 1 (P1), sat in June 2023. The buttons open Pearson's own files.

The official paper and mark scheme

Sit it under exam conditions: open the paper, press Start timer, press Finish when time is up, then mark it against the mark scheme.

Marked it? Worked solutions to 3 similar P1 questions are just below, then every P1 topic to practise.

3 P1 questions like these, with worked solutions

Written and checked by us, not taken from the Pearson paper. Try each one, then tap "Worked solution" to see every step and its marks.

  1. Algebra · 7 marks

    Let f(x)=5−4x−2x2.

    (a) Express f(x) in the form A−B(x+C)2, where A, B, and C are integers.
    (b) State the maximum value of f(x) and the value of x at which it occurs.
    (c) Solve f(x)=0, giving your answers in exact form.

    Worked solution

    (a) M1 Factors out −2 from the x terms: 5−2(x2+2x).

    1. M1 Completes the square inside the bracket: 5−2((x+1)2−1).
    2. A1 Expands and simplifies to obtain 7−2(x+1)2.

    (b) B1 States the maximum value is 7.

    1. B1 States this occurs at x=−1.

    (c) M1 Sets 7−2(x+1)2=0 and rearranges to (x+1)2=72.

    1. A1 Solves for x by square rooting, yielding x=−1±72 (or equivalent exact surd).
  2. Differentiation · 6 marks

    The tangents to the curve y=x2−4x at the points where x=1 and x=3 intersect at a point P. Find the coordinates of P.

    Worked solution
    1. M1 for finding the y-coordinates: at x=1,y=−3 and at x=3,y=−3.
    2. M1 for differentiating dydx=2x−4 to find the gradients: m1=−2 (at x=1) and m3=2 (at x=3).
    3. M1 for finding the equation of the first tangent: y−(−3)=−2(x−1)⟹y=−2x−1.
    4. M1 for finding the equation of the second tangent: y−(−3)=2(x−3)⟹y=2x−9.
    5. M1 for equating the two tangent equations: −2x−1=2x−9⟹4x=8⟹x=2.
    6. A1 for finding the corresponding y-coordinate y=−5, giving P(2,−5).
  3. Graphs and Transformations · 4 marks

    Show that the line y=2x−7 does not intersect the curve y=x2−3x+5.

    Worked solution
    1. M1 for equating the line and the curve: x2−3x+5=2x−7.
    2. M1 for rearranging into a quadratic equation: x2−5x+12=0.
    3. M1 for calculating the discriminant: b2−4ac=(−5)2−4(1)(12)=25−48=−23.
    4. A1 for concluding that since the discriminant is less than zero, there are no real roots, and thus no points of intersection.

More on these topics: Algebra · Differentiation · Graphs and Transformations

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What's on this paper

What this paper is like

WMA11/01: question by question

Labels and topics are ours, read from the WMA11/01 paper (checked 2026-11-01); marks as printed. Tap a number to practise that topic.

  1. Q1Quadratic inequality (4 marks) · P1 Algebra
  2. Q2Inequalities for a sports pitch (6 marks) · P1 Algebra
  3. Q3Completing the square and a sketch (6 marks) · P1 Algebra
  4. Q4Writing in index form, then differentiating (7 marks) · P1 Differentiation
  5. Q5Garden plan: arcs and areas (10 marks) · P1 Trigonometry
  6. Q6Expanding brackets with surds (7 marks) · P1 Algebra
  7. Q7Regions defined by lines and inequalities (6 marks) · P1 Coordinate Geometry, P1 Algebra
  8. Q8Tangent to a curve and where it meets an axis (10 marks) · P1 Differentiation
  9. Q9Identifying a trig graph and its transformation (9 marks) · P1 Trigonometry
  10. Q10Quadratic curve and two lines (10 marks) · P1 Coordinate Geometry

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Questions students ask

Where is the P1 June 2023 mark scheme?

The mark scheme button above opens Pearson's own copy.

What are the grade boundaries for IAL P1 June 2023?

On Pearson's grade boundaries page (opens in a new tab), under June 2023.