TMUA: Quantifiers and negation
Paper 2: quantifiers and negation.
- Section 2 (Paper 2) · Arg1-Arg4 The logic of arguments · spec Arg3-Arg4
- Paper 2 only
- 11 practice questions
- No calculator
What the specification covers
- for all, for some (at least one), there exists
- Negating: not (for all x, P) = there exists x with not P
- Negating and/or statements (De Morgan in words)
Key ideas
- 'For all \(x\), P(\(x\))' is negated by 'there exists \(x\) with not P(\(x\))'.
- 'There exists \(x\) with P(\(x\))' is negated by 'for all \(x\), not P(\(x\))'.
- 'Not (A and B)' is '(not A) or (not B)'; 'not (A or B)' is '(not A) and (not B)'. 'Or' is inclusive.
- The negation of \(x>2\) is \(x\le2\).
Common mistakes
- The order of quantifiers matters: 'for every \(x\) there is a \(y\)' differs from 'there is a \(y\) for every \(x\)'.
- Negate every part, including the inequality signs.
Exam tip
Negate from the outside in: flip each quantifier, then negate the inside.
Worked example
Worked example
Which of the following is the negation of the statement: 'For every real number \(x\) there is an integer \(n\) with \(n>x\)'?
- There is a real number \(x\) and an integer \(n\) with \(n\le x\).
- For every real number \(x\), every integer \(n\) satisfies \(n\le x\).
- For every real number \(x\) there is an integer \(n\) with \(n\le x\).
- There is a real number \(x\) such that every integer \(n\) satisfies \(n\le x\).
- There is an integer \(n\) such that every real number \(x\) satisfies \(n\le x\).
Answer: D: There is a real number \(x\) such that every integer \(n\) satisfies \(n\le x\).
'Not (for every \(x\), P(\(x\)))' is 'there is an \(x\) with not P(\(x\))'. And 'not (there is an \(n\) with \(n>x\))' is 'every \(n\) has \(n\le x\)'. So the negation is 'there is a real \(x\) such that every integer \(n\) satisfies \(n\le x\)'. (The original statement is true, so its negation is false.)
Practice questions
Try each question before opening the solution. No calculator: the TMUA does not allow one. Every answer here was re-checked independently by computer before it was published.
Question 1
Which of the following is the negation of the statement '\(x>2\) and \(y\le5\)'?
- \(x\le2\) or \(y\ge5\)
- \(x>2\) or \(y\le5\)
- \(x<2\) or \(y>5\)
- \(x\le2\) or \(y>5\)
- \(x\le2\) and \(y>5\)
Show the answer and solution
Answer: D: \(x\le2\) or \(y>5\)
'Not (A and B)' is '(not A) or (not B)'. Not \(x>2\) is \(x\le2\); not \(y\le5\) is \(y>5\).
Question 2
Let \(S=\{1,2,3,4,5,6\}\). Which of the following statements are true?
I For every \(a\) in \(S\) there is a \(b\) in \(S\) with \(a+b=7\).
II There is a \(b\) in \(S\) such that for every \(a\) in \(S\), \(ab\) is even.
III For every \(a\) in \(S\) there is a \(b\) in \(S\), with \(b\ne a\), such that \(a\) divides \(b\).
- I and III only
- III only
- I only
- I and II only
- none of them
- II only
- II and III only
- I, II and III
Show the answer and solution
Answer: D: I and II only
I: take \(b=7-a\), which is in \(S\). II: \(b=2\) works for every \(a\). III fails for \(a=4\): the only multiple of 4 in \(S\) is 4 itself.
Question 3
Which of the following is the negation of the statement '\(x\ge1\) or \(y\ge0\)'?
- \(x<1\) or \(y<0\)
- \(x<1\) and \(y<0\)
- \(x\ge1\) and \(y\ge0\)
- \(x\ge1\) and \(y<0\)
- \(x<1\) and \(y\ge0\)
Show the answer and solution
Answer: B: \(x<1\) and \(y<0\)
'Not (P or Q)' is '(not P) and (not Q)'. Not \(x\ge1\) is \(x<1\) and not \(y\ge0\) is \(y<0\).
Question 4
Which of the following is the negation of the statement '\(x\le0\) and \(y\ge-3\)'?
- \(x\le0\) or \(y\ge-3\)
- \(x>0\) and \(y<-3\)
- \(x\le0\) or \(y<-3\)
- \(x>0\) or \(y<-3\)
- \(x>0\) or \(y\ge-3\)
Show the answer and solution
Answer: D: \(x>0\) or \(y<-3\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x\le0\) is \(x>0\) and not \(y\ge-3\) is \(y<-3\).
Question 5
Which of the following is the negation of the statement '\(x<0\) and \(y<6\)'?
- \(x\ge0\) or \(y\ge6\)
- \(x<0\) or \(y\ge6\)
- \(x\ge0\) and \(y\ge6\)
- \(x\ge0\) or \(y<6\)
- \(x<0\) or \(y<6\)
Show the answer and solution
Answer: A: \(x\ge0\) or \(y\ge6\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x<0\) is \(x\ge0\) and not \(y<6\) is \(y\ge6\).
Question 6
Which of the following is the negation of the statement '\(x<2\) and \(y<-3\)'?
- \(x\ge2\) and \(y\ge-3\)
- \(x<2\) or \(y\ge-3\)
- \(x<2\) or \(y<-3\)
- \(x\ge2\) or \(y<-3\)
- \(x\ge2\) or \(y\ge-3\)
Show the answer and solution
Answer: E: \(x\ge2\) or \(y\ge-3\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x<2\) is \(x\ge2\) and not \(y<-3\) is \(y\ge-3\).
Question 7
Which of the following is the negation of the statement '\(x\le0\) and \(y\ge5\)'?
- \(x\le0\) or \(y<5\)
- \(x>0\) or \(y<5\)
- \(x>0\) and \(y<5\)
- \(x\le0\) or \(y\ge5\)
- \(x>0\) or \(y\ge5\)
Show the answer and solution
Answer: B: \(x>0\) or \(y<5\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x\le0\) is \(x>0\) and not \(y\ge5\) is \(y<5\).
Question 8
Which of the following is the negation of the statement '\(x\le2\) and \(y<3\)'?
- \(x>2\) or \(y<3\)
- \(x>2\) or \(y\ge3\)
- \(x\le2\) or \(y<3\)
- \(x>2\) and \(y\ge3\)
- \(x\le2\) or \(y\ge3\)
Show the answer and solution
Answer: B: \(x>2\) or \(y\ge3\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x\le2\) is \(x>2\) and not \(y<3\) is \(y\ge3\).
Question 9
Which of the following is the negation of the statement '\(x>-3\) and \(y\ge1\)'?
- \(x\le-3\) or \(y<1\)
- \(x>-3\) or \(y<1\)
- \(x\le-3\) or \(y\ge1\)
- \(x>-3\) or \(y\ge1\)
- \(x\le-3\) and \(y<1\)
Show the answer and solution
Answer: A: \(x\le-3\) or \(y<1\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x>-3\) is \(x\le-3\) and not \(y\ge1\) is \(y<1\).
Question 10
Which of the following is the negation of the statement '\(x\ge6\) and \(y>1\)'?
- \(x\ge6\) or \(y>1\)
- \(x\ge6\) or \(y\le1\)
- \(x<6\) and \(y\le1\)
- \(x<6\) or \(y\le1\)
- \(x<6\) or \(y>1\)
Show the answer and solution
Answer: D: \(x<6\) or \(y\le1\)
'Not (P and Q)' is '(not P) or (not Q)'. Not \(x\ge6\) is \(x<6\) and not \(y>1\) is \(y\le1\).
Keep going
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