Skip to main content

STEP integration: guide and practice problems

STEP integration is about choosing the right substitution or spotting the symmetry, then carrying out a long calculation without slips.

Where it comes from: Integration in A Level Pure; improper integrals, reduction formulae and volumes in Further Pure.

Key ideas

Common traps

Practice problems

Original problems in the style of STEP. Try each one for at least 20 minutes before you open a hint; write a full solution, then compare.

Problem 1: A reduction formula and a limit · STEP 2 style

For integers \(n\ge0\) let \(I_n=\displaystyle\int_0^1x^ne^x\,dx\).

  1. Show that \(I_n=e-nI_{n-1}\) for \(n\ge1\), and find \(I_3\) in terms of \(e\).
  2. Show that \(0
  3. Deduce the value of \(\displaystyle\lim_{n\to\infty}nI_n\).
Hint 1

Integrate by parts with \(u=x^n\), \(dv=e^xdx\).

Hint 2

For (iii), rearrange the reduction formula: \(nI_{n-1}=e-I_n\). What happens to \(I_n\)?

Full solution

(i) \(I_n=\left[x^ne^x\right]_0^1-n\int_0^1x^{n-1}e^xdx=e-nI_{n-1}\). \(I_0=e-1\), \(I_1=e-(e-1)=1\), \(I_2=e-2\), \(I_3=e-3(e-2)=6-2e\).

(ii) On \((0,1)\), \(0

(iii) From (ii), \(I_n\to0\). From the reduction formula, \(nI_{n-1}=e-I_n\to e\). So \((n-1)I_{n-1}=nI_{n-1}-I_{n-1}\to e\), that is \(\lim nI_n=e\).

Results: \(I_3=6-2e\); \(\lim nI_n=e\).

2 more integration problems

Symmetry on a quarter-turn; Area and volume to infinity. Each with two hints and a full solution.

Included with A Level plans, and with IB, IGCSE or CBSE plans.

Next steps

Related topics: Sequences, series and induction · Functions and curve sketching. Stuck? Read the problem-solving strategies. Ready for the real thing? Official STEP past papers.

STEP is run by OCR. A Level Math Revision is independent: it is not affiliated with or endorsed by OCR, the University of Cambridge or any university. Every problem here is our own, written in the style of STEP; for real papers use OCR's official past papers.